(3x+2)(2x^2-13x-7)=0

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Solution for (3x+2)(2x^2-13x-7)=0 equation: 


Simplifying
(3x + 2)(2x2 + -13x + -7) = 0

Reorder the terms:
(2 + 3x)(2x2 + -13x + -7) = 0

Reorder the terms:
(2 + 3x)(-7 + -13x + 2x2) = 0

Multiply (2 + 3x) * (-7 + -13x + 2x2)
(2(-7 + -13x + 2x2) + 3x * (-7 + -13x + 2x2)) = 0
((-7 * 2 + -13x * 2 + 2x2 * 2) + 3x * (-7 + -13x + 2x2)) = 0
((-14 + -26x + 4x2) + 3x * (-7 + -13x + 2x2)) = 0
(-14 + -26x + 4x2 + (-7 * 3x + -13x * 3x + 2x2 * 3x)) = 0
(-14 + -26x + 4x2 + (-21x + -39x2 + 6x3)) = 0

Reorder the terms:
(-14 + -26x + -21x + 4x2 + -39x2 + 6x3) = 0

Combine like terms: -26x + -21x = -47x
(-14 + -47x + 4x2 + -39x2 + 6x3) = 0

Combine like terms: 4x2 + -39x2 = -35x2
(-14 + -47x + -35x2 + 6x3) = 0

Solving
-14 + -47x + -35x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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